(n^2-3n+1)(2n+3)=0

Solution for (n^2-3n+1)(2n+3)=0 equation:

Simplifying
(n2 + -3n + 1)(2n + 3) = 0

Reorder the terms:
(1 + -3n + n2)(2n + 3) = 0

Reorder the terms:
(1 + -3n + n2)(3 + 2n) = 0

Multiply (1 + -3n + n2) * (3 + 2n)
(1(3 + 2n) + -3n * (3 + 2n) + n2(3 + 2n)) = 0
((3 * 1 + 2n * 1) + -3n * (3 + 2n) + n2(3 + 2n)) = 0
((3 + 2n) + -3n * (3 + 2n) + n2(3 + 2n)) = 0
(3 + 2n + (3 * -3n + 2n * -3n) + n2(3 + 2n)) = 0
(3 + 2n + (-9n + -6n2) + n2(3 + 2n)) = 0
(3 + 2n + -9n + -6n2 + (3 * n2 + 2n * n2)) = 0
(3 + 2n + -9n + -6n2 + (3n2 + 2n3)) = 0

Combine like terms: 2n + -9n = -7n
(3 + -7n + -6n2 + 3n2 + 2n3) = 0

Combine like terms: -6n2 + 3n2 = -3n2
(3 + -7n + -3n2 + 2n3) = 0

Solving
3 + -7n + -3n2 + 2n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.